filter(elements, path)
public
Given an array of nodes it filters the array based on the path. The result
is that when this method returns, the array will contain elements which match the path
Show source
def QuickPath::filter elements, path
return elements if path.nil? or path == '' or elements.size == 0
case path
when /^\/\//
return axe( elements, "descendant-or-self", $' )
when /^\/?\b(\w[-\w]*)\b::/
return axe( elements, $1, $' )
when /^\/(?=\b([:!\w][-\.\w]*:)?[-!\*\.\w]*\b([^:(]|$)|\*)/
rest = $'
results = []
elements.each do |element|
results |= filter( element.to_a, rest )
end
return results
when /^\/?(\w[-\w]*)\(/
return function( elements, $1, $' )
when Namespace::NAMESPLIT
name = $2
ns = $1
rest = $'
elements.delete_if do |element|
!(element.kind_of? Element and
(element.expanded_name == name or
(element.name == name and
element.namespace == Functions.namespace_context[ns])))
end
return filter( elements, rest )
when /^\/\[/
matches = []
elements.each do |element|
matches |= predicate( element.to_a, path[1..-1] ) if element.kind_of? Element
end
return matches
when /^\[/
return predicate( elements, path )
when /^\/?\.\.\./
return axe( elements, "ancestor", $' )
when /^\/?\.\./
return filter( elements.collect{|e|e.parent}, $' )
when /^\/?\./
return filter( elements, $' )
when /^\*/
results = []
elements.each do |element|
results |= filter( [element], $' ) if element.kind_of? Element
end
return results
end
return []
end
RSpec
Ruby on Rails
Ruby
= private
= protected
