bsearch
- 1_8_6_287
- 1_8_7_72
- 1_8_7_330
- 1_9_1_378
- 1_9_2_180
- 1_9_3_125
- 1_9_3_392
- 2_1_10 (0)
- 2_2_9 (0)
- 2_4_6 (0)
- 2_5_5 (38)
- 2_6_3 (0)
- What's this?
bsearch()
public
By using binary search, finds a value from this array which meets the given condition in O(log n) where n is the size of the array.
You can use this method in two use cases: a find-minimum mode and a find-any mode. In either case, the elements of the array must be monotone (or sorted) with respect to the block.
In find-minimum mode (this is a good choice for typical use case), the block must return true or false, and there must be an index i (0 <= i <= ary.size) so that:
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the block returns false for any element whose index is less than i, and
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the block returns true for any element whose index is greater than or equal to i.
This method returns the i-th element. If i is equal to ary.size, it returns nil.
ary = [0, 4, 7, 10, 12] ary.bsearch {|x| x >= 4 } #=> 4 ary.bsearch {|x| x >= 6 } #=> 7 ary.bsearch {|x| x >= -1 } #=> 0 ary.bsearch {|x| x >= 100 } #=> nil
In find-any mode (this behaves like libc’s bsearch(3)), the block must return a number, and there must be two indices i and j (0 <= i <= j <= ary.size) so that:
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the block returns a positive number for ary[k] if 0 <= k < i,
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the block returns zero for ary[k] if i <= k < j, and
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the block returns a negative number for ary[k] if j <= k < ary.size.
Under this condition, this method returns any element whose index is within i…j. If i is equal to j (i.e., there is no element that satisfies the block), this method returns nil.
ary = [0, 4, 7, 10, 12] # try to find v such that 4 <= v < 8 ary.bsearch {|x| 1 - x / 4 } #=> 4 or 7 # try to find v such that 8 <= v < 10 ary.bsearch {|x| 4 - x / 2 } #=> nil
You must not mix the two modes at a time; the block must always return either true/false, or always return a number. It is undefined which value is actually picked up at each iteration.