link_to_if(condition, name, options = {}, html_options = {}, *parameters_for_method_reference, &block) public

Create a link tag of the given name using an URL created by the set of options, if condition is true, in which case only the name is returned (or the given block is yielded, if one exists).

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October 30, 2009
2 thanks

Outputs name even if condition is false

Please note that if the condition is false, link_to_if will still output the name given as a plain text (as documented above). If you want nothing printed at all, you’ll have to stay with the old and trusty:

link_to "Login", ... if @current_user.nil?
March 30, 2015
0 thanks

If condition is false, options hash is ignored

Here, the class will be ignored:

<%= link_to_if false, 'Home', root_path, class: 'link' %> 
#=> Home
October 30, 2009
0 thanks

Outputs name even if condition is false

Please note that if the condition is false, link_to_if will still output the name given as a plain text (as documented above). If you want nothing printed at all, you’ll have to stay with the old and trusty:

link_to "Login", ... if @current_user.nil?
March 30, 2015
0 thanks

Passing a block does not behave as expected

When the condition is true, the block is not rendered:

<%= link_to_if true, users_path, {}, {} do %>
  <i class='fa fa-star'></i>
<% end %>

renders:

<a href="/users">/users</a>

But if the condition is false, the block will render:

<%= link_to_if false, users_path, {}, {} do %>
  <i class='fa fa-star'></i>
<% end %>

renders:

<i class='fa fa-star'></i>