unescape(*arg)
public
Synopsis
URI.unescape(str)
Args
str |
Unescapes the string.
|
Usage
require 'uri'
enc_uri = URI.escape("http://example.com/?a=\11\15")
p enc_uri
p URI.unescape(enc_uri)
Show source
def unescape(*arg)
warn "#{caller(1)[0]}: warning: URI.unescape is obsolete" if $VERBOSE
DEFAULT_PARSER.unescape(*arg)
end