method

have_framework

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have_framework(fw, &b) public

Returns whether or not the given framework can be found on your system. If found, a macro is passed as a preprocessor constant to the compiler using the framework name, in uppercase, prepended with HAVE_FRAMEWORK_.

For example, if have_framework(‘Ruby’) returned true, then the HAVE_FRAMEWORK_RUBY preprocessor macro would be passed to the compiler.

If fw is a pair of the framework name and its header file name that header file is checked, instead of the normally used header file which is named same as the framework.

Show source

# File lib/mkmf.rb, line 1080
  def have_framework(fw, &b)
    if Array === fw
      fw, header = *fw
    else
      header = "#{fw}.h"
    end
    checking_for fw do
      src = cpp_include("#{fw}/#{header}") << "\n" "int main(void){return 0;}"
      opt = " -framework #{fw}"
      if try_link(src, "-ObjC#{opt}", &b)
        $defs.push(format("-DHAVE_FRAMEWORK_%s", fw.tr_cpp))
        # TODO: non-worse way than this hack, to get rid of separating
        # option and its argument.
        $LDFLAGS << " -ObjC" unless /(\A|\s)-ObjC(\s|\z)/ =~ $LDFLAGS
        $LIBS << opt
        true
      else
        false
      end
    end
  end

have_framework

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