method

>=

Ruby latest stable (v1_8_7_72) - 1 note - Class: Module

>=(p1) public

Returns true if mod is an ancestor of other, or the two modules are the same. Returns nil if there’s no relationship between the two. (Think of the relationship in terms of the class definition: "class A<B" implies "B>A").

Show source

/*
 * call-seq:
 *   mod >= other   =>  true, false, or nil
 *
 * Returns true if <i>mod</i> is an ancestor of <i>other</i>, or the
 * two modules are the same. Returns 
 * <code>nil</code> if there's no relationship between the two. 
 * (Think of the relationship in terms of the class definition: 
 * "class A<B" implies "B>A").
 *
 */

static VALUE
rb_mod_ge(mod, arg)
    VALUE mod, arg;
{
    switch (TYPE(arg)) {
      case T_MODULE:
      case T_CLASS:
        break;
      default:
        rb_raise(rb_eTypeError, "compared with non class/module");
    }

    return rb_class_inherited_p(arg, mod);
}

January 11, 2010

0 thanks

Includes all ancestors

May be helpful to know that this returns true if B is any ancestor of A, not just a direct one. As an example:

 class Foo; end
 class Bar < Foo; end
 class Baz < Bar; end

 Foo >= Bar #=> true
 Foo >= Baz #=> true

>=

Related methods

Includes all ancestors